本文共 13854 字,大约阅读时间需要 46 分钟。
功能:实现用神经网络对多样本数据进行分类训练
改进方法:应该把每次训练好的参数写入txt或json中,可以通过选择是否重新训练来调节 预测速度和 准确率的关系
demo.py
import numpy as npimport matplotlib.pyplot as pltfrom planar_utils import plot_decision_boundary, sigmoid, load_planar_datasetdef layer_sizes(X, Y): """ Arguments: X -- input dataset of shape (input size, number of examples) Y -- labels of shape (output size, number of examples) Returns: n_x -- the size of the input layer n_h -- the size of the hidden layer n_y -- the size of the output layer """ ### START CODE HERE ### (≈ 3 lines of code) n_x = X.shape[0] # size of input layer n_y = Y.shape[0] # size of output layer ### END CODE HERE ### return (n_x, n_y) np.random.seed(1) # set a seed so that the results are consistentdef initialize_parameters(n_x, n_h, n_y): """ Argument: n_x -- size of the input layer n_h -- size of the hidden layer n_y -- size of the output layer Returns: params -- python dictionary containing your parameters: W1 -- weight matrix of shape (n_h, n_x) b1 -- bias vector of shape (n_h, 1) W2 -- weight matrix of shape (n_y, n_h) b2 -- bias vector of shape (n_y, 1) """ np.random.seed(2) # we set up a seed so that your output matches ours although the initialization is random. ### START CODE HERE ### (≈ 4 lines of code) W1 = np.random.randn(n_h, n_x)*0.01 b1 = np.zeros((n_h, 1)) W2 = np.random.randn(n_y, n_h)*0.01 b2 = np.zeros((n_y, 1)) ### END CODE HERE ### assert (W1.shape == (n_h, n_x)) assert (b1.shape == (n_h, 1)) assert (W2.shape == (n_y, n_h)) assert (b2.shape == (n_y, 1)) parameters = {"W1": W1, "b1": b1, "W2": W2, "b2": b2} return parametersdef forward_propagation(X, parameters): """ Argument: X -- input data of size (n_x, m) parameters -- python dictionary containing your parameters (output of initialization function) Returns: A2 -- The sigmoid output of the second activation cache -- a dictionary containing "Z1", "A1", "Z2" and "A2" """ # Retrieve each parameter from the dictionary "parameters" ### START CODE HERE ### (≈ 4 lines of code) W1 = parameters['W1'] b1 = parameters['b1'] W2 = parameters['W2'] b2 = parameters['b2'] ### END CODE HERE ### # Implement Forward Propagation to calculate A2 (probabilities) ### START CODE HERE ### (≈ 4 lines of code) Z1 = np.dot(W1, X) + b1 A1 = np.tanh(Z1) Z2 = np.dot(W2, A1) + b2 A2 = sigmoid(Z2) ### END CODE HERE ### assert(A2.shape == (1, X.shape[1])) cache = {"Z1": Z1, "A1": A1, "Z2": Z2, "A2": A2} return A2, cachedef compute_cost(A2, Y, parameters): """ Computes the cross-entropy cost given in equation (13) Arguments: A2 -- The sigmoid output of the second activation, of shape (1, number of examples) Y -- "true" labels vector of shape (1, number of examples) parameters -- python dictionary containing your parameters W1, b1, W2 and b2 Returns: cost -- cross-entropy cost given equation (13) """ m = float(Y.shape[1]) # number of example # Compute the cross-entropy cost ### START CODE HERE ### (≈ 2 lines of code) logprobs = np.multiply(np.log(A2),Y) + np.multiply((1-Y), (np.log(1-A2))) cost = -1/m * np.sum(logprobs) ### END CODE HERE ### cost = np.squeeze(cost) # makes sure cost is the dimension we expect. # E.g., turns [[17]] into 17 assert(isinstance(cost, float)) return costdef backward_propagation(parameters, cache, X, Y): """ Implement the backward propagation using the instructions above. Arguments: parameters -- python dictionary containing our parameters cache -- a dictionary containing "Z1", "A1", "Z2" and "A2". X -- input data of shape (2, number of examples) Y -- "true" labels vector of shape (1, number of examples) Returns: grads -- python dictionary containing your gradients with respect to different parameters """ m = float(X.shape[1]) # First, retrieve W1 and W2 from the dictionary "parameters". ### START CODE HERE ### (≈ 2 lines of code) W1 = parameters['W1'] W2 = parameters['W2'] ### END CODE HERE ### # Retrieve also A1 and A2 from dictionary "cache". ### START CODE HERE ### (≈ 2 lines of code) A1 = cache['A1'] A2 = cache['A2'] ### END CODE HERE ### # Backward propagation: calculate dW1, db1, dW2, db2. ### START CODE HERE ### (≈ 6 lines of code, corresponding to 6 equations on slide above) dZ2= A2 - Y dW2 =1/m * np.dot(dZ2, A1.T) db2 =1/m * np.sum(dZ2, axis=1, keepdims=True) dZ1 = np.dot(W2.T, dZ2) * (1 - np.power(A1, 2)) dW1 = 1/m * np.dot(dZ1, X.T) db1 =1/m * np.sum(dZ1, axis=1, keepdims=True) ### END CODE HERE ### grads = {"dW1": dW1, "db1": db1, "dW2": dW2, "db2": db2} return gradsdef update_parameters(parameters, grads, learning_rate = 1.2): """ Updates parameters using the gradient descent update rule given above Arguments: parameters -- python dictionary containing your parameters grads -- python dictionary containing your gradients Returns: parameters -- python dictionary containing your updated parameters """ # Retrieve each parameter from the dictionary "parameters" ### START CODE HERE ### (≈ 4 lines of code) W1 = parameters['W1'] b1 = parameters['b1'] W2 = parameters['W2'] b2 = parameters['b2'] ### END CODE HERE ### # Retrieve each gradient from the dictionary "grads" ### START CODE HERE ### (≈ 4 lines of code) dW1 = grads["dW1"] db1 = grads["db1"] dW2 = grads["dW2"] db2 = grads["db2"] ## END CODE HERE ### # Update rule for each parameter ### START CODE HERE ### (≈ 4 lines of code) W1 = W1 - learning_rate * dW1 b1 = b1 - learning_rate * db1 W2 = W2 - learning_rate * dW2 b2 = b2 - learning_rate * db2 ### END CODE HERE ### parameters = {"W1": W1, "b1": b1, "W2": W2, "b2": b2} return parametersdef nn_model(X, Y, n_h, num_iterations = 10000, print_cost=False): """ Arguments: X -- dataset of shape (2, number of examples) Y -- labels of shape (1, number of examples) n_h -- size of the hidden layer num_iterations -- Number of iterations in gradient descent loop print_cost -- if True, print the cost every 1000 iterations Returns: parameters -- parameters learnt by the model. They can then be used to predict. """ np.random.seed(3) # Initialize parameters, then retrieve W1, b1, W2, b2. Inputs: "n_x, n_h, n_y". Outputs = "W1, b1, W2, b2, parameters". ### START CODE HERE ### (≈ 5 lines of code) n_x, n_y = layer_sizes(X, Y) parameters = initialize_parameters(n_x, n_h, n_y) ### END CODE HERE ### # Loop (gradient descent) for i in range(0, num_iterations): ### START CODE HERE ### (≈ 4 lines of code) # Forward propagation. Inputs: "X, parameters". Outputs: "A2, cache". A2,cache = forward_propagation(X, parameters) # Cost function. Inputs: "A2, Y, parameters". Outputs: "cost". cost = compute_cost(A2, Y, parameters) # Backpropagation. Inputs: "parameters, cache, X, Y". Outputs: "grads". grads = backward_propagation(parameters, cache, X, Y) # Gradient descent parameter update. Inputs: "parameters, grads". Outputs: "parameters". parameters = update_parameters(parameters, grads) ### END CODE HERE ### # Print the cost every 1000 iterations if print_cost and i % 1000 == 0: print ("Cost after iteration %i: %f" %(i, cost)) return parametersdef predict(parameters, X): """ Using the learned parameters, predicts a class for each example in X Arguments: parameters -- python dictionary containing your parameters X -- input data of size (n_x, m) Returns predictions -- vector of predictions of our model (red: 0 / blue: 1) """ # Computes probabilities using forward propagation, and classifies to 0/1 using 0.5 as the threshold. ### START CODE HERE ### (≈ 2 lines of code) A2, cache = forward_propagation(X, parameters) predictions = np.array( [1 if x >0.5 else 0 for x in A2.reshape(-1,1)] ).reshape(A2.shape) # 这一行代码的作用详见下面代码示例 ### END CODE HERE ### return predictionsX, Y = load_planar_dataset()# print(X.shape) #(2, 400) 在load中进行了转置,其中2代表单个样本特征数,400 代表样本数# print(Y.shape) #(1, 400) 在load中进行了转置,本例中1代表输出层个数,400 代表样本数plt.scatter(X[0, :], X[1, :], c=Y, s=40); #c代表色彩或颜色序列 s代表标量或形如shape[n,]数组# Build a model with a n_h-dimensional hidden layerparameters = nn_model(X, Y, n_h = 4, num_iterations = 10000, print_cost=True) # Plot the decision boundaryplot_decision_boundary(lambda x: predict(parameters, x.T), X, Y)pre = predict(parameters, X)print ('training accuracy: %.2f' % (np.mean(pre == Y[0])))plt.title("Decision Boundary for hidden layer size " + str(4))plt.show()
planar_utils.py
'''Created on 2018年7月18日@author: hcl'''import matplotlib.pyplot as pltimport numpy as npdef plot_decision_boundary(model, X, y): # Set min and max values and give it some padding x_min, x_max = X[0, :].min() - 1, X[0, :].max() + 1 y_min, y_max = X[1, :].min() - 1, X[1, :].max() + 1 h = 0.01 # Generate a grid of points with distance h between them xx, yy = np.meshgrid(np.arange(x_min, x_max, h), np.arange(y_min, y_max, h)) # Predict the function value for the whole grid Z = model(np.c_[xx.ravel(), yy.ravel()]) Z = Z.reshape(xx.shape) # Plot the contour and training examples plt.contourf(xx, yy, Z) plt.ylabel('x2') plt.xlabel('x1') plt.scatter(X[0, :], X[1, :], c=y) def sigmoid(x): """ Compute the sigmoid of x Arguments: x -- A scalar or numpy array of any size. Return: s -- sigmoid(x) """ s = 1/(1+np.exp(-x)) return sdef load_planar_dataset(): np.random.seed(1) m = 400 # number of examples N = int(m/2) # number of points per class D = 2 # dimensionality X = np.zeros((m,D)) # data matrix where each row is a single example Y = np.zeros((m,1), dtype='uint8') # labels vector (0 for red, 1 for blue) a = 4 # maximum ray of the flower for j in range(2): ix = range(N*j,N*(j+1)) t = np.linspace(j*3.12,(j+1)*3.12,N) + np.random.randn(N)*0.2 # theta r = a*np.sin(4*t) + np.random.randn(N)*0.2 # radius X[ix] = np.c_[r*np.sin(t), r*np.cos(t)] Y[ix] = j X = X.T Y = Y.T return X, Y
输出:
Cost after iteration 0: 0.693048Cost after iteration 1000: 0.288083Cost after iteration 2000: 0.254385Cost after iteration 3000: 0.233864Cost after iteration 4000: 0.226792Cost after iteration 5000: 0.222644Cost after iteration 6000: 0.219731Cost after iteration 7000: 0.217504Cost after iteration 8000: 0.219504Cost after iteration 9000: 0.218571training accuracy: 0.91
1:通过修改对应的X Y数据集 可以训练不同的数据
X = np.array([ [0,0,1], [1,1,1], [1,0,1], [0,1,1] ]).TY = np.array([[0,1,1,0]])
输出;
Cost after iteration 0: 0.693173Cost after iteration 1000: 0.000294Cost after iteration 2000: 0.000138Cost after iteration 3000: 0.000090Cost after iteration 4000: 0.000066Cost after iteration 5000: 0.000052Cost after iteration 6000: 0.000043Cost after iteration 7000: 0.000037Cost after iteration 8000: 0.000032Cost after iteration 9000: 0.000028
2:在planar_utils.py中添加
并在开头导入:import sklearn.datasets
def load_extra_datasets(): N = 200 noisy_circles = sklearn.datasets.make_circles(n_samples=N, factor=.5, noise=.3) noisy_moons = sklearn.datasets.make_moons(n_samples=N, noise=.2) blobs = sklearn.datasets.make_blobs(n_samples=N, random_state=5, n_features=2, centers=6) gaussian_quantiles = sklearn.datasets.make_gaussian_quantiles(mean=None, cov=0.5, n_samples=N, n_features=2, n_classes=2, shuffle=True, random_state=None) no_structure = np.random.rand(N, 2), np.random.rand(N, 2) return noisy_circles, noisy_moons, blobs, gaussian_quantiles, no_structure
在demo.py中 导入load_extra_datasets
并将X Y数据来源 改为:
noisy_circles, noisy_moons, blobs, gaussian_quantiles, no_structure = load_extra_datasets()datasets = {'noisy_circles':noisy_circles, 'noisy_moons':noisy_moons, 'blobs':blobs, 'gaussian_quantiles':gaussian_quantiles, }dataset = 'noisy_moons'X,Y = datasets[dataset]X,Y = X.T, Y.reshape(1,Y.shape[0])if dataset == 'blobs': Y = Y % 2 plt.scatter(X[0, :], X[1, :], c=Y, s=40)
训练输出:
Cost after iteration 0: 0.692994Cost after iteration 1000: 0.299064Cost after iteration 2000: 0.131752Cost after iteration 3000: 0.124443Cost after iteration 4000: 0.121406Cost after iteration 5000: 0.118751Cost after iteration 6000: 0.116311Cost after iteration 7000: 0.114297Cost after iteration 8000: 0.112747Cost after iteration 9000: 0.111537training accuracy: 0.95
3、查看不同隐藏层节点数对预测数据精确度的影响
在获取X Y数据集以后:
plt.figure(figsize=(16, 32))hidden_layer_sizes = [1, 2, 3, 4, 5, 20, 50]for i, n_h in enumerate(hidden_layer_sizes): plt.subplot(5, 2, i+1) plt.title('Hidden Layer of size %d' % n_h) parameters = nn_model(X, Y, n_h, num_iterations = 5000) plot_decision_boundary(lambda x: predict(parameters, x.T), X, Y) predictions = predict(parameters, X) accuracy = float((np.dot(Y,predictions.T) + np.dot(1-Y,1-predictions.T))/float(Y.size)*100) print ("Accuracy for {} hidden units: {} %".format(n_h, accuracy))plt.show()
输出:
Accuracy for 1 hidden units: 67.5 %Accuracy for 2 hidden units: 67.25 %Accuracy for 3 hidden units: 90.75 %Accuracy for 4 hidden units: 90.5 %Accuracy for 5 hidden units: 91.25 %Accuracy for 20 hidden units: 90.0 %Accuracy for 50 hidden units: 90.75 %